🔌 Embedded · Electronics
Circuit basics (#1–6)

Voltage drop

Rds(on)Heatwiki/embedded-voltage-drop
TL;DR

Voltage drop is the phenomenon where current passing through a part such as a resistor consumes and loses voltage by V=IR; in a series circuit the sum of each part's drops must equal the supply voltage, a direct consequence of KVL. With a 12V battery and two 6Ω resistors in series, 1A flows and each resistor drops 6V, so the total 12V matches the supply. When large motor currents flow, as in a kickboard BLDC, drops across wiring, MOSFETs, shunts, and battery internal resistance turn into weakened output and heat, making this the starting point for voltage-divider, internal-resistance, and power-loss calculations.

The concept in one line, with a water analogy

  • Voltage drop is the amount of voltage consumed, equal to V=IR, as current passes through a part.
  • By the water analogy it is like water pressure dropping through a narrow pipe: the battery pushes voltage, and it falls as current passes the resistor (the narrow pipe).
  • Ohm's law (V=IR) gives each part's drop, and KVL guarantees that their sum equals the supply voltage.

Working it with numbers — 12V with two 6Ω in series

  • Total resistance R = 6 + 6 = 12Ω, and total current I = V/R = 12V/12Ω = 1A.
  • Each resistor's drop is V_drop = I × R = 1A × 6Ω = 6V; following the circuit, 12V falls to 6V after the first resistor and to 0V after the second.
  • The drops sum to 6V + 6V = 12V, exactly the supply voltage, as guaranteed by KVL.
voltage drop at that part [V]
current through the part [A] — same everywhere in series
resistance of that part [Ω]
Each part's drop = current through it × that part's resistance

Kickboard/STM32 context — where drops occur

  • Wiring has small resistance, but large current makes its drop grow, lowering motor voltage and weakening output.
  • A MOSFET's Rds(on) turns current × Rds(on) into heat that lowers efficiency, while battery internal resistance causes voltage sag where terminal voltage falls as load grows.
  • A shunt resistor uses an intentional drop to measure current, and ultimately the answer to 'why does the motor weaken under large current' is voltage drop.
📉Where voltage drop occurs
🔌Wiringlarge current → weaker output
🔥MOSFET Rds(on)current × Rds(on) = heat
📏Shunt resistorintentional drop to measure current
🔋Battery internal Rheavier load → voltage sag
Where voltage drop occurs and what it causes
Pitfalls & gotchas

A voltage drop is not waste but each part taking its share by V=IR, and KVL guarantees their sum equals the supply voltage. Heat is I²×R (power loss), so at large currents even a small drop produces large heat — the basis for choosing wire gauge and MOSFETs.

The topic cards on this page are compiled from the Brain Trinity wiki. The original wiki can be demoed live in an interview.Back to study log